document.write( "Question 916520: 1)degree 3 with a zero 2(of multiplicity 3) such that f(3)=-4
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document.write( "2) degree 3 with a zeros -2(of multiplicity 2) and -4 such that f(-5)=10
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document.write( "3) degree 4 with zeros 1 and 3 (of multiplicity 3) such that f(5)=16 \n" );
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Algebra.Com's Answer #556116 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! 1. y = a(x-2)^3 P(3,-4) \n" ); document.write( " -4 = a (1)^3 \n" ); document.write( "y = -4(x-2)^3 \n" ); document.write( "... \n" ); document.write( "2. y = a(x+2)^2(x+4) P(-5,10) \n" ); document.write( "10 = a(-3)^2(-1) \n" ); document.write( "10/-9 = a \n" ); document.write( "y = -10/9(x+2)^2(x+4) \n" ); document.write( "... \n" ); document.write( "3.y = a(x-1)(x-3)^3 P(5,16) \n" ); document.write( "16= a(4)(2)^3 \n" ); document.write( "16/32 = a \n" ); document.write( "y = (1/2)(x-1)(x-3)^3 \n" ); document.write( " |