document.write( "Question 916527: if log(x)=2.3675 and log( y)= 0.9750.find the value of x+y \n" ); document.write( "
Algebra.Com's Answer #556100 by Edwin McCravy(20056)\"\" \"About 
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log(x)=2.3675 and log( y)= 0.9750.find the value of x+y
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document.write( "Use the principle of changing a log equation into an exponential\r\n" );
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document.write( "The log equation logB(A) = C\r\n" );
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document.write( "is equivalent to the exponential equation A = BC.\r\n" );
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document.write( "Also use the fact that when no base is written, the base is \r\n" );
document.write( "understood to be 10.\r\n" );
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document.write( "So in this problem, log(A) = C is equivalent to A = 10C.\r\n" );
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document.write( "log(x) = 2.3675 is equivalent to\r\n" );
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document.write( "x = 102.3675\r\n" );
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document.write( "which by calculator is 233.0773115\r\n" );
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document.write( "AND\r\n" );
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document.write( "log(y) = 0.9750 is equivalent to\r\n" );
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document.write( "y = 100.9750\r\n" );
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document.write( "which by calculator is 9.4406088\r\n" );
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document.write( "THEREFORE\r\n" );
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document.write( "x + y = 233.0773115 + 9.4406088 = 242.5179203 \r\n" );
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document.write( "Edwin
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