document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=916175>Question 916175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sides of a triangle are 6, 8 and 15 cm long. In a simikar triangle, the longest side is 21 cm long. Find the other two sides.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #556056 by </B><A HREF=/tutors/aboutme.mpl?userid=Hawksfan><B>Hawksfan(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Hawksfan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Hawksfan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=556056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a ratio problem. lets call the unknown sides x and y.\r<BR>\n" );
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document.write( "Since the 21 is the longest side of 2nd triangle, we compare it to 15, the longest side of the first triangle.\r<BR>\n" );
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document.write( "   21/15 = x/6\r<BR>\n" );
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document.write( "simplify\r<BR>\n" );
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document.write( "  7/5 = x/6\r<BR>\n" );
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document.write( "multiply by 6\r<BR>\n" );
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document.write( "x = 42/5\r<BR>\n" );
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document.write( "now find the other side y\r<BR>\n" );
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document.write( "21/15 = y/8\r<BR>\n" );
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document.write( "7/5 = y/8\r<BR>\n" );
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document.write( "56/8 =y  or y = 56/8 = 7 </SPAN>\n" );
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