document.write( "Question 916442: Let 2^a = 6 and 2^b = 7. Using exponent rules, solve the equation in terms of a and/or b.
\n" ); document.write( "6^x = 64 \n" ); document.write( "
Algebra.Com's Answer #556049 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since 2^a = 6, we can replace 6 with 2^a\r
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\n" ); document.write( "\n" ); document.write( "6^x = 64\r
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\n" ); document.write( "\n" ); document.write( "(2^a)^x = 64\r
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\n" ); document.write( "\n" ); document.write( "log( (2^a)^x ) = log( 64 )\r
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\n" ); document.write( "\n" ); document.write( "x*log(2^a) = log(64)\r
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\n" ); document.write( "\n" ); document.write( "x = log(64)/log(2^a)\r
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\n" ); document.write( "\n" ); document.write( "Let me know if you need more help or if you need me to explain a step in more detail.
\n" ); document.write( "Feel free to email me at jim_thompson5910@hotmail.com
\n" ); document.write( "or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html\r
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\n" ); document.write( "\n" ); document.write( "Thanks,\r
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\n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( "
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