document.write( "Question 916288: if sinx = 1/2 and cosx = (the square root of 3)/2, evaluate secx \n" ); document.write( "

Algebra.Com's Answer #555998 by ewatrrr(24785) $\"\"$ $\"About$

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secx = 2/√3 = 2√3/3
\n" ); document.write( "θ radians sin θ cos θ tan θ
\n" ); document.write( "0° 0 0 1 0
\n" ); document.write( "30° π/6 1/2 √3/2 √3/3
\n" ); document.write( "45° π/4 √2/2 √2/2 1
\n" ); document.write( "60° π/3 √3/2 1/2 √3
\n" ); document.write( "90° π/2 1 0 ─
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