document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=916113>Question 916113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Forty percent of job applicants are rejected in a random sample of 12 applicants, what is the probability that at least 2 are rejected? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555939 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Population: p(rejected) = .40<BR>\n" );
document.write( "Sample: n = 12, <BR>\n" );
document.write( "P(x >= 2) = 1 - binomcdf(12, .40, 1)<BR>\n" );
document.write( "0r w/o TI<BR>\n" );
document.write( "P(x >= 2) = 1 - P(0) - P(1) = 1 - .60^12 - 12C1(.40)^1(.60)^11 </SPAN>\n" );
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