document.write( "Question 916118: The perimeter of a garden is 66 meters and its area is 270 m2. Find the dimensions of the garden. \n" ); document.write( "
Algebra.Com's Answer #555930 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
Dimensions x and y;
\n" ); document.write( "p=66
\n" ); document.write( "xy=270
\n" ); document.write( "Use A=xy\r
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\n" ); document.write( "\n" ); document.write( "The question happens often as an academic exercise.
\n" ); document.write( "A, p known.
\n" ); document.write( "x, y unknown.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2x+2y=p and xy=A.
\n" ); document.write( "\"2y=p-2x\"
\n" ); document.write( "\"y=%28p-2x%29%2F2\"
\n" ); document.write( "-
\n" ); document.write( "\"x%28p-2x%29%2F2=A\"
\n" ); document.write( "\"x%28p-2x%29=2A\"
\n" ); document.write( "\"xp-2x%5E2=2A\"
\n" ); document.write( "\"-2x%5E2%2Bxp-2A=0\"
\n" ); document.write( "\"2x%5E2-xp%2B2A=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You can continue symbolically like this and use formula for solution of a quadratic equation, or you can substitute the given values for p and A now, and reach your values for x and y.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%5E2-66x%2B2%2A270=0\"
\n" ); document.write( "\"x%5E2-33x%2B270=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=%2833%2B-+sqrt%2833%5E2-4%2A270%29%29%2F2\"
\n" ); document.write( "\"x=%2833%2B-+sqrt%289%29%29%2F2\"
\n" ); document.write( "\"x=%2833%2B-+3%29%2F2\"
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "The dimensions are 15 and 18.
\n" ); document.write( "
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