document.write( "Question 916112: Given sinA:4/5, cosB=5/13 both A and B in quadrant I, find tan(A+B) \n" ); document.write( "
Algebra.Com's Answer #555927 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Given sinA:4/5, cosB=5/13 both A and B in quadrant I, find tan(A+B) \n" ); document.write( "*** \n" ); document.write( "sinA=4/5 \n" ); document.write( "cosA=3/5(working with a 3-4-5 reference right triangle) \n" ); document.write( ".. \n" ); document.write( "cosB=5/13 \n" ); document.write( "sinB=12/13(working with a 5-12-13 reference right triangle) \n" ); document.write( ".. \n" ); document.write( "sin(A+B)=sinAcosB+cosAsinB=4/5*5/13+3/5*12/13=20/65+36/65=56/65 \n" ); document.write( "cos(A+B)=cosAcosB-sinAsinB=3/5*5/13-4/5*12/13=15/65-48/65=-33/65 \n" ); document.write( "tan(A+B)=sin(A+B)/cos(A+B)=-56/33 \n" ); document.write( ".. \n" ); document.write( "Check: \n" ); document.write( "sinA=4/5 \n" ); document.write( "A=53.13˚ \n" ); document.write( "cosB=5/13 \n" ); document.write( "B=67.38˚ \n" ); document.write( "A+B=53.13+67.38=120.51˚ \n" ); document.write( "tan(A+B)=tan(120.51˚)=-1.6969... \n" ); document.write( "as calculated: tan(A+B)=-56/33=-1.6969... \n" ); document.write( " |