document.write( "Question 916121: Given cosA=1/3,A is quadrant IV and cosB=-squareroot7/4: B is in quadrant II find cos(A-B) \n" ); document.write( "
Algebra.Com's Answer #555925 by lwsshak3(11628)\"\" \"About 
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Given cosA=1/3,A is quadrant IV and cosB=-squareroot7/4: B is in quadrant II find cos(A-B)
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\n" ); document.write( "sinA=-√(1-cos^2A)=-√(1-1/9)=-√(8/9)=-√8/3
\n" ); document.write( "sinB=√(1-cos^2B)=√(1-7/16)=√(9/16)=3/4
\n" ); document.write( "..
\n" ); document.write( "cos(A-B)
\n" ); document.write( "=cosAcosB+sinAsinB
\n" ); document.write( "=1/3*-√7/4+(-√8/3)*3/4
\n" ); document.write( "=-√7/12-3√8/12
\n" ); document.write( "=-(√7+3√8)/12
\n" ); document.write( "..
\n" ); document.write( "Check:
\n" ); document.write( "cosA=1/3
\n" ); document.write( "A=289.47˚
\n" ); document.write( "cosB=-√7/4
\n" ); document.write( "B=131.41˚
\n" ); document.write( "A-B=289.47-131.41=158.06
\n" ); document.write( "cos(A-B)=cos(158.06˚)=-0.9276...
\n" ); document.write( "as calculated:cos(A-B)=-(√7+3√8)/12=-0.9276...
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