document.write( "Question 916121: Given cosA=1/3,A is quadrant IV and cosB=-squareroot7/4: B is in quadrant II find cos(A-B) \n" ); document.write( "
Algebra.Com's Answer #555925 by lwsshak3(11628)    ![]() You can put this solution on YOUR website! Given cosA=1/3,A is quadrant IV and cosB=-squareroot7/4: B is in quadrant II find cos(A-B) \n" ); document.write( "*** \n" ); document.write( "sinA=-√(1-cos^2A)=-√(1-1/9)=-√(8/9)=-√8/3 \n" ); document.write( "sinB=√(1-cos^2B)=√(1-7/16)=√(9/16)=3/4 \n" ); document.write( ".. \n" ); document.write( "cos(A-B) \n" ); document.write( "=cosAcosB+sinAsinB \n" ); document.write( "=1/3*-√7/4+(-√8/3)*3/4 \n" ); document.write( "=-√7/12-3√8/12 \n" ); document.write( "=-(√7+3√8)/12 \n" ); document.write( ".. \n" ); document.write( "Check: \n" ); document.write( "cosA=1/3 \n" ); document.write( "A=289.47˚ \n" ); document.write( "cosB=-√7/4 \n" ); document.write( "B=131.41˚ \n" ); document.write( "A-B=289.47-131.41=158.06 \n" ); document.write( "cos(A-B)=cos(158.06˚)=-0.9276... \n" ); document.write( "as calculated:cos(A-B)=-(√7+3√8)/12=-0.9276... \n" ); document.write( "  |