document.write( "Question 916108: Hello I need help with given sinA= 4/5 cosB= 5/13 both A and B in quadrant I, find tan(A+B)
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Algebra.Com's Answer #555910 by mananth(16946)\"\" \"About 
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\n" ); document.write( "sinA= 4/5\r
\n" ); document.write( "\n" ); document.write( "sin^2A=16/25
\n" ); document.write( "1-cos^2A=16/25
\n" ); document.write( "cos^2A=9/25\r
\n" ); document.write( "\n" ); document.write( "cos A = 3/5\r
\n" ); document.write( "\n" ); document.write( "sin A / cos A = (4/5) / (3/5)\r
\n" ); document.write( "\n" ); document.write( "tan A = 4/3\r
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\n" ); document.write( "\n" ); document.write( "cosB= 5/13 \r
\n" ); document.write( "\n" ); document.write( "tan B = 12/5\r
\n" ); document.write( "\n" ); document.write( "tan(A + B) = [ tan A + tan B ] / [ 1 - tan A tan B] \r
\n" ); document.write( "\n" ); document.write( "= (4/3 + 12/5) /(1-(4/3)(12/5))\r
\n" ); document.write( "\n" ); document.write( "=(56/15)/(-33/15)\r
\n" ); document.write( "\n" ); document.write( "=-56/33
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