document.write( "Question 916040: Please help me solve this equation: sqrt(2x+3)-sqrt(x+1)=1\r
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Algebra.Com's Answer #555903 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%282x%2B3%29-sqrt%28x%2B1%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "1. Isolate one of the square roots by subtracting the other from both sides. In this case, I will add \"-sqrt%28x%2B1%29\" from both sides, giving us\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%282x%2B3%29=1%2Bsqrt%28x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "2. Square both sides so that we eliminate the root on the left side. This will give us\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B3=1%2B2%2Asqrt%28x%2B1%29%2Bx%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "3. Combine like terms on the right side, giving us\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B3=2%2B2%2Asqrt%28x%2B1%29%2Bx\"\r
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\n" ); document.write( "\n" ); document.write( "4. Subtract the 2 on the right side from both sides of the equal sign, which gives us\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B3-2=2%2Asqrt%28x%2B1%29%2Bx\"----->\"2x%2B1=2%2Asqrt%28x%2B1%29%2Bx\"\r
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\n" ); document.write( "\n" ); document.write( "5. Subtract the x on the right side from both sides of the equal sign, which gives us\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B1-x=2%2Asqrt%28x%2B1%29\"----->\"x%2B1=2%2Asqrt%28x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "6. Divide both sides of the equation by 2, giving us\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%2F2=sqrt%28x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "7. Square both sides of the equal sign to eliminate the radical on the right side, giving us\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B2x%2B1%29%2F4=x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "8. Multiply both sides of the equal sign by 4 to get rid of the fraction on the left side, giving us:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x%2B1=4x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "9. Place all terms on the left side of the equation and set the equation equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x-4x%2B1-4=0\"----->\"x%5E2-2x-3=0\"\r
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\n" ); document.write( "\n" ); document.write( "10. Factor the left side of the equation, which will give us\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%28x-3%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "11. Set each factor equal to 0 and solve for x for both factors:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B1=0\"and\"x-3=0\"----->\"x=-1\" and \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "12. Verify that both of these values of x work, by plugging them into the original equation and making sure when plugged in, they equal 1.\r
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\n" ); document.write( "\n" ); document.write( "Final Answer: x = -1 , 3
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