document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=916022>Question 916022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The rectangular field in the following illustration is surrounded by 72 meters of fencing. If the field is partitioned as shown, a total of 88 meters of fencing is required. Find the dimensions of the field.\r<BR>\n" );
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document.write( "Here is the illustration: http://imgur.com/HRZwHUl </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555887 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L + 2W = 72 (the perimeter)<BR>\n" );
document.write( "3L (to account for the extra fencing down the middle) + 2W = 88<BR>\n" );
document.write( "The difference between the two is 16, so the extra L is 16.<BR>\n" );
document.write( "Plug that into the original perimeter equation.<BR>\n" );
document.write( "2(16) + 2W = 72<BR>\n" );
document.write( "32 + 2W = 72<BR>\n" );
document.write( "2W = 40<BR>\n" );
document.write( "W = 20<BR>\n" );
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