document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=915894>Question 915894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It says to evaluate(solve) the arithmetic series:\r<BR>\n" );
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document.write( "20+27+34+41..., n=16\r<BR>\n" );
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document.write( "How do you do this? Please help. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555859 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of an arithmetic sequence is given by the following formula,<BR>\n" );
document.write( "(n/2)*(a1 + an), which is the sum of the first n terms<BR>\n" );
document.write( "the nth term an is given by the following formula<BR>\n" );
document.write( "an = a1 + (n-1)d, where d is the common difference, therefore<BR>\n" );
document.write( "a16 = 20 + (16-1)*7<BR>\n" );
document.write( "a16 = 20 + 105 = 125<BR>\n" );
document.write( "now the sum is (16/2)*(20 + 125) = 1160<BR>\n" );
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