document.write( "Question 915911: Janet can do a job in 3 hours while Garry can do the same job in 2 hours. If Janet works for an hour before Garry helps her, how long will it take them to finish the job together?
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Algebra.Com's Answer #555825 by josgarithmetic(39617)\"\" \"About 
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Person___________rate__________time__________job
\n" ); document.write( "Gary_____________1/2____________2_____________1
\n" ); document.write( "Janet____________1/3____________3_____________1
\n" ); document.write( "BOTH___________1/2+1/3_________________________\r
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\n" ); document.write( "\n" ); document.write( "Rate of BOTH together is \"5%2F6\" jobs per hour.\r
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\n" ); document.write( "\n" ); document.write( "Let t be the time during which they both work together (to finish the job).\r
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\n" ); document.write( "\n" ); document.write( "Person_________rate_______time________job
\n" ); document.write( "Janet__________1/2_________1__________(1/2)*1
\n" ); document.write( "Gary&Janet_____5/6_________t__________(5/6)t
\n" ); document.write( "TOTAL__________________________________1\r
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\n" ); document.write( "\n" ); document.write( "Solve for t in the equation \"highlight%281%2F2%2B%285%2F6%29t=1%29\"
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