document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=915868>Question 915868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the times required to service customers' cars at a repair shop are skewed to the right with a mean of 2.5 hours and a standard deviation of 0.75. what can be said about proportion of cars whose service time is either less than one hour or more than four hours?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555793 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> skewed right means the distribution 'tails off' on the right<BR>\n" );
document.write( "That is to say there are more observations on the left side.<BR>\n" );
document.write( "....<BR>\n" );
document.write( "mean = 2.5 hours and sd =  0.75<BR>\n" );
document.write( "what can be said about proportion of cars whose service time is either less than one hour or more than four hours?<BR>\n" );
document.write( "p < 2SD from mean on the left vs  p > 2SD from mean on the right<BR>\n" );
document.write( "skewed right...likely there are proportionately  more < 1hr </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );