document.write( "Question 915799: pls help me to answer, A long wire is cut into three smaller pcs in the ratio of 7:3:2. if the shortest pcs is 16 cm,what is the area of the largest rectangle that can be created using the longest piece? \n" ); document.write( "

Algebra.Com's Answer #555751 by rothauserc(4718) $\"\"$ $\"About$

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A long wire is cut into three smaller pcs in the ratio of 7:3:2
\n" ); document.write( "We are given that the shortest piece is 16 cm, then the ratio factor is 8 (8*2 = 16),
\n" ); document.write( "therefore the longest piece is 7*8 = 56
\n" ); document.write( "perimeter (P) of a rectangle is 2l + 2w where l is length and w is width, then
\n" ); document.write( "2l + 2w = 56
\n" ); document.write( "divide both sides of = by 2
\n" ); document.write( "l + w = 28
\n" ); document.write( "Area (A) of rectangle = l*w
\n" ); document.write( "we want the maximum area of A, remember that all squares are rectangles but all rectangles are not squares
\n" ); document.write( "therefore,
\n" ); document.write( "max A = 14 * 14 = 196 cm^2 \n" ); document.write( "

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