document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77476>Question 77476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the diameter is 200 ft. whatwill be the area of the surface? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55575 by </B><A HREF=/tutors/aboutme.mpl?userid=aaaaaaaa><B>aaaaaaaa(138)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aaaaaaaa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I don't know if the approximate value of pi is given. If it is, substitute and multiply on the last equation; if it's not, the result I'll end up with is probably the intended one.\r<BR>\n" );
document.write( "\n" );
document.write( "First of all, the formula for the area of a circle is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+d%2Api ALIGN=MIDDLE  ALT=\"A+=+d%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore, the area of our circle is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+200%2Api ALIGN=MIDDLE  ALT=\"A+=+200%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" > feet. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );