document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=915771>Question 915771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio,the liquids in both the vessels be mixed to obtain a new mixture in vessel C containing half milk and half water?<BR>\n" );
document.write( "2)Two numbers A and B are such that the sum of 5% of A and 4% of B is 2/3rd of the sum of 6% of A and 8% of B. The ratio A:B is ?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555744 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555744\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Milk in 1 litre mixture of A = 4/7 litre.<BR>\n" );
document.write( " Milk in 1 litre mixture of B = 2/5 litre.<BR>\n" );
document.write( " Milk in 1 litre mixture of C = 1/2 litre.<BR>\n" );
document.write( " By rule of alligation we have required ratio X:Y \r<BR>\n" );
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document.write( "   X                  :                 Y\r<BR>\n" );
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document.write( " 4/7                                2/5<BR>\n" );
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document.write( "            (Mean ratio)<BR>\n" );
document.write( "                   (1/2)\r<BR>\n" );
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document.write( "(1/2 – 2/5)     :       (4/7 – 1/2)\r<BR>\n" );
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document.write( "      1/10                      1/1 4\r<BR>\n" );
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document.write( "Required ratio = X : Y = 1/10 : 1/14 = 7:5\r<BR>\n" );
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document.write( "Two numbers A and B are such that the sum of 5% of A and 4% of B is 2/3rd of the sum of 6% of A and 8% of B. The ratio A:B is ?\r<BR>\n" );
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document.write( "0.05A+0.04B= 2/3( 0.06A+0.08B)\r<BR>\n" );
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document.write( "0.15A +0.12B= 0.12A+0.16B\r<BR>\n" );
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document.write( "0.03A=0.04B\r<BR>\n" );
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document.write( "A/B = 4/3 </SPAN>\n" );
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