document.write( "Question 915729: A car leaves St. Paul, Minnesota at 4 pm. A bus leaves the same place at 5 pm and travels in the same direction as the car. the car is 12 mph faster than the bus. at 8 pm the vehicles are 100 mi apart. What is the speed of each vehicle?
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Algebra.Com's Answer #555722 by mananth(16946)\"\" \"About 
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A car leaves St. Paul, Minnesota at 4 pm. A bus leaves the same place at 5 pm and travels in the same direction as the car. the car is 12 mph faster than the bus. at 8 pm the vehicles are 100 mi apart. What is the speed of each vehicle? \r
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\n" ); document.write( "\n" ); document.write( "A car leaves St. Paul, Minnesota at 4 pm.
\n" ); document.write( " A bus leaves the same place at 5 pm and travels in the same direction as the car. speed =x mph
\n" ); document.write( " the car is 12 mph faster than the bus. (x+12) mph\r
\n" ); document.write( "\n" ); document.write( "d= rt
\n" ); document.write( "Car time = 4 hours
\n" ); document.write( "distance traveled = 4(x+12)\r
\n" ); document.write( "\n" ); document.write( "Bus time = 3 hours
\n" ); document.write( "Bus distance = 3x\r
\n" ); document.write( "\n" ); document.write( "Difference between them = 100 miles\r
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\n" ); document.write( "\n" ); document.write( "4(x+12)-3x=100\r
\n" ); document.write( "\n" ); document.write( "4x+48-3x=100\r
\n" ); document.write( "\n" ); document.write( "x=52 \r
\n" ); document.write( "\n" ); document.write( "Bus speed = 52 mph
\n" ); document.write( "car speed = 52 +12 = 64 mph\r
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\n" ); document.write( "\n" ); document.write( "64*4 -52*3=100\r
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\n" ); document.write( "\n" ); document.write( "at 8 pm the vehicles are 100 mi apart. What is the speed of each vehicle?
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