document.write( "Question 77385: Solve each equation.\r
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document.write( "a+4/2 = a+4/a\r
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document.write( "and\r
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document.write( "4w-1/3w+6 - w-1/3 = w-1/w+2 \n" );
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Algebra.Com's Answer #55572 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve each equation. \n" ); document.write( ": \n" ); document.write( "I have to assume what you mean here, a few brackets would help a lot. \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Cross multiply and you have: \n" ); document.write( "a(a+4) = 2(a+4) \n" ); document.write( "a^2 + 4a = 2a + 8 \n" ); document.write( "a^2 + 4a - 2a - 8 = 0 \n" ); document.write( "a^2 + 2a - 8 = 0; a quadratic equation \n" ); document.write( "Factors to: \n" ); document.write( "(a+4)(a-2) = 0 \n" ); document.write( "a = -4 \n" ); document.write( "and \n" ); document.write( "a = +2 \n" ); document.write( ": \n" ); document.write( "Check both solutions in the original equation \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Factor out 3 in the 1st denominator: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply thru by the common denominator, 3(w+2), you then have \n" ); document.write( " (4w-1) - ((w-1)(w+2)) = 3(w-1) \n" ); document.write( ": \n" ); document.write( "FOIL (w-1)(w+2) and what's inside the brackets: \n" ); document.write( "(4w-1) - (w^2 + w - 2) = 3w - 3 \n" ); document.write( ": \n" ); document.write( "Remove the brackets: \n" ); document.write( "4w - 1 - w^2 - w + 2 = 3w - 3 \n" ); document.write( "-w^2 + 3w + 1 = 3w - 3 \n" ); document.write( "-w^2 + 3w - 3w + 1 + 3 = 0 \n" ); document.write( "-w^2 + 4 = 0 \n" ); document.write( "w^2 - 4 = 0; Multiplied equation by -1 \n" ); document.write( "w^2 = +4 \n" ); document.write( "w = +2 \n" ); document.write( ": \n" ); document.write( "Check the solution, substitute 2 for w in the original equation \n" ); document.write( " |