document.write( "Question 915652: A rectangle has perimeter 38 feet and an area of 88 square feet. Find the dimensions of the rectangle assuming the width is smaller than the length. \n" ); document.write( "
Algebra.Com's Answer #555717 by josgarithmetic(39616)![]() ![]() ![]() You can put this solution on YOUR website! Dimensions x and y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+2y=38 and xy=88.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter equation simplifies to x+y=19.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve the system, |