document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=915661>Question 915661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kg of a 45% copper alloy must be added to 62kg of a 60% copper alloy to form an alloy, which is 50% copper. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555691 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555691\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many kg of a 45% copper alloy must be added to 62kg of a 60% copper alloy to form an alloy, which is 50% copper.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "copper + copper = copper<BR>\n" );
document.write( "0.45x + 0.60*62 = 0.50(x+62)<BR>\n" );
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document.write( "45x + 60*62 = 50x + 50*62<BR>\n" );
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document.write( "5x = 10*62<BR>\n" );
document.write( "x = 124 kg (amt. of 45% alloy needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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