document.write( "Question 915620: The larger of printing presses can print a job in four hours. If both presses together, they can print the same job in two hours and 24 minutes. How long would it take the smaller press to print the job alone? \n" ); document.write( "

Algebra.Com's Answer #555685 by josmiceli(19441) $\"\"$ $\"About$

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Add their rates of printing to find
\n" ); document.write( "their rate printing together
\n" ); document.write( " $\"+24+\"$ min = $\"+2%2F5+\"$ hrs
\n" ); document.write( " $\"+2+=+10%2F5+\"$ hrs
\n" ); document.write( " $\"+1%2F4+%2B+1%2Ft+=+1%2F%28%2812%2F5%29%29+\"$
\n" ); document.write( " $\"+1%2F4+%2B+1%2Ft+=+5%2F12+\"$
\n" ); document.write( "Multiply both sides by $\"+12t+\"$
\n" ); document.write( " $\"+3t+%2B+12+=+5t+\"$
\n" ); document.write( " $\"+2t+=+12+\"$
\n" ); document.write( " $\"+t+=+6+\"$
\n" ); document.write( "The smaller press prints the job in 6 hrs
\n" ); document.write( "check:
\n" ); document.write( " $\"+1%2F4+%2B+1%2F6+=+5%2F12+\"$
\n" ); document.write( " $\"+3%2F12+%2B+2%2F12+=+5%2F12+\"$
\n" ); document.write( " $\"+5%2F12+=+5%2F12+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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