document.write( "Question 915598: ashley's parents drives in one car at a steady rate of 40 miles per hour. Brittany's family leave 2 hours later and drives at a constant rate of 50 miles per hour. Both families arrive at the grandparents' house at the same time! what is the distance from ashley's house to the grandparents' house?
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Algebra.Com's Answer #555674 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Ashley's parents got a head start of $\"+40%2A2+=+80+\"$ mi
\n" ); document.write( "Start a stopwatch when Brittany's family leaves.
\n" ); document.write( "Let $\"+d+\"$ = the distance in miles from Ashley's house
\n" ); document.write( "to grandparent's house
\n" ); document.write( "Let $\"+t+\"$ = time in hrs on the stopwatch
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\n" ); document.write( "Equation for Ashley's parents:
\n" ); document.write( "(1) $\"+d+-+80+=+40t+\"$
\n" ); document.write( "equation for Brittany's family:
\n" ); document.write( "(2) $\"+d+=+50t+\"$
\n" ); document.write( "----------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) $\"+50t+-+80+=+40t+\"$
\n" ); document.write( "(1) $\"+10t+=+80+\"$
\n" ); document.write( "(1) $\"+t+=+8+\"$
\n" ); document.write( "--------------
\n" ); document.write( "(2) $\"+d+=+50%2A8+\"$
\n" ); document.write( "(2) $\"+d+=+400+\"$
\n" ); document.write( "The distance from ashley's house
\n" ); document.write( "to the grandparents' house is 400 mi
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\n" ); document.write( "Check:
\n" ); document.write( "(1) $\"+400+-+80+=+40t+\"$
\n" ); document.write( "(1) $\"+320+=+40t+\"$
\n" ); document.write( "(1) $\"+t+=+8+\"$
\n" ); document.write( "OK\r
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