document.write( "Question 915469: ann, donna, fay, bob, and carl all want to go to the movies but ann and donna got into a fight and can not sit together in the movie theater. how many ways can they be seated in a row?
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Algebra.Com's Answer #555620 by josmiceli(19441)\"\" \"About 
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This would be all the possible ways that
\n" ); document.write( "the 5 of them can sit together minus
\n" ); document.write( "the ways that Ann and Donna can be
\n" ); document.write( "seated together:
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\n" ); document.write( "The ways 5 people can sit together is:
\n" ); document.write( "\"+5%2A4%2A3%2A2%2A1+=+120+\"
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\n" ); document.write( "The ways Ann and donna can sit together is:
\n" ); document.write( "a d x x x
\n" ); document.write( "d a x x x
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\n" ); document.write( "x a d x x
\n" ); document.write( "x d a x x
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\n" ); document.write( "x x a d x
\n" ); document.write( "x x d a x
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\n" ); document.write( "x x x a d
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\n" ); document.write( "For each of these 8 cases, the x's
\n" ); document.write( "can have:
\n" ); document.write( "\"+3%2A2%2A1+=+6+\" different orderings
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\n" ); document.write( "\"+6%2A8+=+48+\"
\n" ); document.write( "and \"+120+-+48+=+72+\"
\n" ); document.write( "There are 72 ways they can be seated in a row
\n" ); document.write( "Hope I got it
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