document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=915271>Question 915271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> construct a right angled triangle measure of whose hypotenuse is 5 cm and one side is 3.2 cm (hint:angle in a semi circle is right angle) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555533 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can calculate the other leg length using the Pythagorean theorem,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%5E2=3.2%5E2%2BL%5E2 ALIGN=MIDDLE  ALT=\"5%5E2=3.2%5E2%2BL%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L%5E2=25-10.24 ALIGN=MIDDLE  ALT=\"L%5E2=25-10.24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=3.842 ALIGN=MIDDLE  ALT=\"L=3.842\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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