document.write( "Question 915117: The ones digit of a number is 1 more than twice the tens digit. If the digits are reversed, the new number is 8 less than 3 times the original number. What is the original number? Thanks in advance, and please do hurry up, I need to submit it soon. \n" ); document.write( "
Algebra.Com's Answer #555448 by josmiceli(19441)\"\" \"About 
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Call the original number
\n" ); document.write( "\"+10t+%2B+u+\" where:
\n" ); document.write( "\"+t+\" = the tens digit
\n" ); document.write( "\"+u+\" = the units digit
\n" ); document.write( "-----------------------
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+u+=+2t+%2B+1+\"
\n" ); document.write( "(2) \"+10u+%2B+t+=+3%2A%28+10t+%2B+u+%29+-+8+\"
\n" ); document.write( "-------------------------------
\n" ); document.write( "(2) \"+10u+%2B+t+=+30t+%2B+3u+-+8+\"
\n" ); document.write( "(2) \"+7u+=+29t+-+8+\"
\n" ); document.write( "----------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+7%2A%28+2t+%2B+1+%29+=+29t+-+8+\"
\n" ); document.write( "(2) \"+14t+%2B+7+=+29t+-+8+\"
\n" ); document.write( "(2) \"+15t+=+15+\"
\n" ); document.write( "(2) \"+t+=+1+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+u+=+2t+%2B+1+\"
\n" ); document.write( "(1) \"+u+=+2%2A1+%2B+1+\"
\n" ); document.write( "(1) \"+u+=+3+\"
\n" ); document.write( "---------------
\n" ); document.write( "The original number is 13
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+10u+%2B+t+=+3%2A%28+10t+%2B+u+%29+-+8+\"
\n" ); document.write( "(2) \"+10%2A3+%2B+1+=+3%2A%28+10%2A1+%2B+3+%29+-+8+\"
\n" ); document.write( "(2) \"+31+=+3%2A13+-+8+\"
\n" ); document.write( "(2) \"+31+=+39+-+8+\"
\n" ); document.write( "(2) \"+31+=+31+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" );