document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=915061>Question 915061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Charlie's age is eleven more than twice Sandy's age.  The sum of their ages is 59.  Find each or their ages.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555414 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x Sandy's age<BR>\n" );
document.write( "(2x+11) + x = 59<BR>\n" );
document.write( "3x = 48<BR>\n" );
document.write( "x = 16, Sandy's age.  Charlie is 43  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A16%2B11 ALIGN=MIDDLE  ALT=\"2%2A16%2B11\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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