document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=914984>Question 914984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose both a 6% and 12% alcohol solution are available. How many gallons of each must be mixed in order to get 30 gallons of a 10.5% alcohol solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555373 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We need a total of 30 gal at 10.5%<BR>\n" );
document.write( "We want to know how many gal at 6% to mix with 12%<BR>\n" );
document.write( "a+b=30,<BR>\n" );
document.write( "0.06*a+0.12*b=0.105*30<BR>\n" );
document.write( "a=30-b<BR>\n" );
document.write( "0.06*(30-b)+0.12*b=3.15<BR>\n" );
document.write( "1.8-0.06b+0.12*b=3.15<BR>\n" );
document.write( "0.06*b=1.35<BR>\n" );
document.write( "b=22.5<BR>\n" );
document.write( "a=30-b<BR>\n" );
document.write( "a=7.5 gal at 6%<BR>\n" );
document.write( "b=22.5 gal at 12%<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.06*7.5+0.12*22.5=0.105*30<BR>\n" );
document.write( "0.45+2.7=3.15<BR>\n" );
document.write( "3.15=3.15<BR>\n" );
document.write( "ok<BR>\n" );
document.write( "codemx1<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );