document.write( "Question 914860: Please how do I solve the following problem: Three men do a piece of work, the first does 7/15, the second does 5/6 of the remainder while the third does the rest. If the rest done by the third person equal 24units, find the whole piece of work.
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Algebra.Com's Answer #555324 by mananth(16946) $\"\"$ $\"About$

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Three men do a piece of work, the first does 7/15, the second does 5/6 of the remainder while the third does the rest. If the rest done by the third person equal 24units, find the whole piece of work.\r
\n" ); document.write( "\n" ); document.write( "let total work be 1\r
\n" ); document.write( "\n" ); document.write( "1-7/15= 8/15\r
\n" ); document.write( "\n" ); document.write( "I............ 7/15\r
\n" ); document.write( "\n" ); document.write( "1-7/15= 8/15 (balance)\r
\n" ); document.write( "\n" ); document.write( "5/6 of balance\r
\n" ); document.write( "\n" ); document.write( "II............5/6 * 8/15= 4/9\r
\n" ); document.write( "\n" ); document.write( "Remaining III does\r
\n" ); document.write( "\n" ); document.write( "III......1-(7/15+4/9)\r
\n" ); document.write( "\n" ); document.write( "1-(21+20)/45
\n" ); document.write( "1-41/45
\n" ); document.write( "4/45\r
\n" ); document.write( "\n" ); document.write( "III.............4/45\r
\n" ); document.write( "\n" ); document.write( "4/45 ......................24 units
\n" ); document.write( "1.....................?
\n" ); document.write( "6*45= 270 units\r
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