document.write( "Question 914771: working together, Rick and Juanita can complete a job in 6 hours. It would take Rick 9 hours longer than Juanita to do the job alone. How long would it take Juanita alone? \n" ); document.write( "
Algebra.Com's Answer #555320 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
working together, Rick and Juanita can complete a job in 6 hours. It would take Rick 9 hours longer than Juanita to do the job alone. How long would it take Juanita alone?
\n" ); document.write( "***
\n" ); document.write( "let x=time juanita can do the job alone
\n" ); document.write( "1/x=her work rate
\n" ); document.write( "x+9=time rick can do the job alone
\n" ); document.write( "1/(x+9)=his work rate
\n" ); document.write( "6 hrs=time rick and juanita can finish the job working together
\n" ); document.write( "1/6=their work rate
\n" ); document.write( "..
\n" ); document.write( "sum of indv work rates=work rate working together
\n" ); document.write( "\"1%2Fx%2B1%2F%28x%2B9%29=1%2F6\"
\n" ); document.write( "lcd:x(x+9)
\n" ); document.write( "x+9+x=x(x+9)/6
\n" ); document.write( "12x+54=x^2+9x
\n" ); document.write( "x^2-3x-54=0
\n" ); document.write( "(x+6)(x-9)=0
\n" ); document.write( "x=9
\n" ); document.write( "time juanita can do the job alone=9 hrs
\n" ); document.write( "
\n" );