document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=914785>Question 914785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Provided: e^(4x) + 4e^(2x) &#8722; 12 = 0\r<BR>\n" );
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document.write( "Use the substitution t = e^(2x)\r<BR>\n" );
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document.write( "t^2 = <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555311 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Provided: e^(4x) + 4e^(2x) &#8722; 12 = 0<BR>\n" );
document.write( "Use the substitution t = e^(2x)<BR>\n" );
document.write( "solve for x <BR>\n" );
document.write( "t^2=e^4x<BR>\n" );
document.write( "t^2+4t-12=0<BR>\n" );
document.write( "(t+6)(t-2)=0<BR>\n" );
document.write( "t=2=e^(2x)<BR>\n" );
document.write( "2xlne=ln2<BR>\n" );
document.write( "2x=ln2<BR>\n" );
document.write( "x=ln2/2&#8776;0.36 </SPAN>\n" );
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