document.write( "Question 914766: 1.Alex’s father is five more than twice as old as he is now. Six years ago, he was one-third as old. How old are they now?\r
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Algebra.Com's Answer #555301 by mananth(16946)\"\" \"About 
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1.Alex’s father is five more than twice as old as he is now. Six years ago, he was one-third as old. How old are they now?\r
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\n" ); document.write( "\n" ); document.write( "Let son's age be x
\n" ); document.write( "Father's age = 5+2x\r
\n" ); document.write( "\n" ); document.write( "6 years ago\r
\n" ); document.write( "\n" ); document.write( "son's age = x-6
\n" ); document.write( "Father's age = (2x+5)-6 = 2x-1\r
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\n" ); document.write( "\n" ); document.write( "1/3(2x-1) =(x-6)\r
\n" ); document.write( "\n" ); document.write( "2x-1=3(x-6)
\n" ); document.write( "2x-1=3x-18
\n" ); document.write( "x=17
\n" ); document.write( "Son's age =17 years
\n" ); document.write( "father's age = 5+2x => 5+17*2=39 years\r
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\n" ); document.write( "\n" ); document.write( "2.Two cars traveled the same distance. Car A traveled at 50 miles per hour and car B at 60 miles per hour. It took car A 50 minutes longer to make a trip. How long did it take car B to make the same trip?\r
\n" ); document.write( "\n" ); document.write( "since distance traveled is same\r
\n" ); document.write( "\n" ); document.write( "d= rt
\n" ); document.write( "rt for both is same\r
\n" ); document.write( "\n" ); document.write( "let car be take x hours
\n" ); document.write( "car A takes x+ 5/6 hours\r
\n" ); document.write( "\n" ); document.write( "50(x+5/6) = 60x
\n" ); document.write( "50(6x+5)/6 = 60x
\n" ); document.write( "50(6x+5)=360x
\n" ); document.write( "300x+250=360x
\n" ); document.write( "60x=250
\n" ); document.write( "6x=25
\n" ); document.write( "x= 4.16\r
\n" ); document.write( "\n" ); document.write( "4 hours 10 minutes
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