document.write( "Question 914817: One number is the square of the other. Their sum is 132. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #555300 by mananth(16946)\"\" \"About 
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let the number be x
\n" ); document.write( "other number = x^2\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx=132\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx-132=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B12x-11x-132=0\"\r
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\n" ); document.write( "\n" ); document.write( "x(x+12)-11(x+12)=0\r
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\n" ); document.write( "\n" ); document.write( "(x+12)(x-11)=0\r
\n" ); document.write( "\n" ); document.write( "If x+12=0
\n" ); document.write( "x=-12
\n" ); document.write( "If x-11=0
\n" ); document.write( "x=11\r
\n" ); document.write( "\n" ); document.write( "(-12,144)\r
\n" ); document.write( "\n" ); document.write( "(11,121)\r
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