document.write( "Question 77409: Graph of the following rational functions,give any equations for vertical,horizontal,or oblique asymptotes. Label completely! \r
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document.write( " 6+2x
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document.write( " -4+x \n" );
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Algebra.Com's Answer #55529 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! If we have a 0 as our denominator, then we have a vertical asymptote, so...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So our vertical asymptote is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For our horizontal asymptote, we simply evaluate x for a very large values and see where it ends up. In other words:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It looks like as we let x continue on forever, y will slowly approach the value of 2. So our horizontal asymptote is y=2. It turns out that we simply divide 2x by x to get 2\r \n" ); document.write( "\n" ); document.write( "And since the degrees of the numerator and the denominator are the same, we will not have any oblique asymptotes.\r \n" ); document.write( "\n" ); document.write( "So here's our graph:\r \n" ); document.write( "\n" ); document.write( " |