document.write( "Question 914690: Please help me with this question:\r
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document.write( "Given sinΘ= -3/5, find cos 2Θ\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #555251 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Given sinΘ= -3/5, find cos 2Θ \n" ); document.write( "cos 2Θ=1-2sin^2Θ=1-2(-3/5)^2=1-2(9/25)=1-(18/25)=7/25 \n" ); document.write( "cos 2Θ=7/25 \n" ); document.write( " |