document.write( "Question 914576: A car traveling at 48 mph overtakes a cyclist who, riding at 12 mph, had a 3 hour head start.  How far from the starting point does the car overtake the cyclist? \n" ); document.write( "
Algebra.Com's Answer #555214 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
A car traveling at 48 mph overtakes a cyclist who, riding at 12 mph, had a 3 hour head start.  How far from the starting point does the car overtake the cyclist?
\n" ); document.write( "

\n" ); document.write( "Let distance traveled to catch-up point, be D
\n" ); document.write( "Then car would've taken \"D%2F48\" to get to catch-up point
\n" ); document.write( "Cyclist would've taken \"D%2F12\" to get to catch-up point
\n" ); document.write( "Both would've covered the same distance, but car's time would be 3 hours less than cycle's time. Therefore, we get:
\n" ); document.write( "\"D%2F48+=+D%2F12+-+3\"
\n" ); document.write( "D = 4D - 144 ------ Multiplying by LCD, 48
\n" ); document.write( "D - 4D = - 144
\n" ); document.write( "- 3D = - 144
\n" ); document.write( "D, or distance traveled to catch-up point (distance from starting point) = \"%28-+144%29%2F%28-+3%29\", or \"highlight_green%2848%29\" miles \n" ); document.write( "
\n" );