document.write( "Question 914529: If A B=10, B C=12 and A C=15 .what is the value of A ? \n" ); document.write( "
Algebra.Com's Answer #555166 by ewatrrr(24785)\"\" \"About 
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Re TY '+' didn't come thru :), Principle the same...
\n" ); document.write( "A+B = 10 0r A = 10-B
\n" ); document.write( "B+C = 12 0r C = 12-B
\n" ); document.write( "A+C = 15
\n" ); document.write( "(10-B) + (12-B) = 15
\n" ); document.write( "22-2B = 15
\n" ); document.write( " 7 = 2B, B = 3.5 , A = 6.5 \"10-3.5\", C = 8.5 \"12-3.5\"
\n" ); document.write( ".............
\n" ); document.write( "AB = 10 0r A = 10/B
\n" ); document.write( "BC = 12 0r C = 12/B
\n" ); document.write( "AC = 15
\n" ); document.write( "\"%2810%2FB%29%2812%2FB%29\" = 15
\n" ); document.write( "\"%2810%2A12%2F15%29\" = B^2
\n" ); document.write( "B^2 = 8
\n" ); document.write( "B = ± \"sqrt%288%29\" = ± \"sqrt%284%2A2%29\"
\n" ); document.write( "B = ± 2√2
\n" ); document.write( " A = 10/B = ± \"10%2F%282sqrt%282%29%29\" = ±\"5sqrt%282%29%2F2\"
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