document.write( "Question 914529: If A B=10, B C=12 and A C=15 .what is the value of A ? \n" ); document.write( "
Algebra.Com's Answer #555166 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Re TY '+' didn't come thru :), Principle the same... \n" ); document.write( "A+B = 10 0r A = 10-B \n" ); document.write( "B+C = 12 0r C = 12-B \n" ); document.write( "A+C = 15 \n" ); document.write( "(10-B) + (12-B) = 15 \n" ); document.write( "22-2B = 15 \n" ); document.write( " 7 = 2B, B = 3.5 , A = 6.5 \n" ); document.write( "............. \n" ); document.write( "AB = 10 0r A = 10/B \n" ); document.write( "BC = 12 0r C = 12/B \n" ); document.write( "AC = 15 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "B^2 = 8 \n" ); document.write( "B = ± \n" ); document.write( "B = ± 2√2 \n" ); document.write( " A = 10/B = ± |