document.write( "Question 914487: 5. The air pressure in a randomly selected tire put on a certain model new car is normally distributed with a mean value 31 psi and standard deviation 1 psi. \r
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\n" ); document.write( "\n" ); document.write( "a) What is the probability that the pressure for a randomly selected tire is between 30 psi and 32 psi?\r
\n" ); document.write( "\n" ); document.write( "b) What is the maximum tire pressure for the bottom 25% of the cars?\r
\n" ); document.write( "\n" ); document.write( "c) What is the median tire pressure of all cars of this model?\r
\n" ); document.write( "\n" ); document.write( "d) If a sample of 25 tires is selected, what is the probability that the average air pressure of these tires is more than 31.5 psi?
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Algebra.Com's Answer #555159 by ewatrrr(24785)\"\" \"About 
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normally distributed with a mean value 31 psi and standard deviation 1 psi.
\n" ); document.write( "a) What is the probability that the pressure for a randomly selected tire is between 30 psi and 32 psi?
\n" ); document.write( "Empirical Rule(1SD from mean) 68%
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\n" ); document.write( "\n" ); document.write( "one standard deviation from the mean accounts for about 68% of the set
\n" ); document.write( "two standard deviations from the mean account for about 95%
\n" ); document.write( "and three standard deviations from the mean account for about 99.7%.
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\n" ); document.write( "0r P = normalcdf(30,32,31,1)
\n" ); document.write( "0r \"z+=blue+%28x+-+mu%29%2Fblue%28sigma%29\" P = normalcdf(-1,1)
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\n" ); document.write( " b) What is the maximum tire pressure X for the bottom 25% of the cars?
\n" ); document.write( "1(invNorm(.25) + 31 = X
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\n" ); document.write( " c) What is the median tire pressure of all cars of this model?
\n" ); document.write( "Normal Distribution(Mean Median & Mode the same): 31 psi
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\n" ); document.write( " d) If a sample of 25 tires is selected, what is the probability that the average air pressure of these tires is more than 31.5 psi?
\n" ); document.write( " \"z+=blue+%28x+-+mu%29%2Fblue%28sigma%2Fsqrt%28n%29%29+=+.5%2F%281%2F5%29\" = 2.5,
\n" ); document.write( "P(x > 31.5) = normalcdf(2.5,100)
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