document.write( "Question 914499: Here's my problem. Please help me. Thank youuu.\r
\n" ); document.write( "\n" ); document.write( "A machineis supposed to mix peanuts, hazelnuts, cashews, and pecans in the ratio 5:2:2:1. A can containing 500 of these mixed nuts was found to have 269 peanuts 74 cashews and 45 pecans. How many hazelnuts are there?
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Algebra.Com's Answer #555149 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
269 peanuts, 74 cashews, and 45 pecans add up to \"269%2B74%2B45=388\" nuts.
\n" ); document.write( "Since there are 500 nuts in the can,
\n" ); document.write( "and each nut is expected to be
\n" ); document.write( "either a peanut, or a hazelnut, or a cashew, or a pecan
\n" ); document.write( "(no almonds, chestnuts, filberts or any other nuts),
\n" ); document.write( "then the remaining \"500-388=highlight%28112%29\" nuts are hazelnuts.
\n" ); document.write( "If you want to write both calculations in one, use parentheses, like this:
\n" ); document.write( "\"500-%28269%2B74%2B45%29=highlight%28112%29\" ,
\n" ); document.write( "or (showing your work)
\n" ); document.write( "\"500-%28269%2B74%2B45%29=500-388=highlight%28112%29\" .
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\n" ); document.write( "Obviously, that machine is not doing a good job, or else it is mixing the bulk product correctly, but the mix segregates (de-mixes a bit) as it is being packaged.
\n" ); document.write( "If the nuts were in the ratio 5:2:2:1,
\n" ); document.write( "we could split that can containing 500 nuts into 50 groups of 10 nuts,
\n" ); document.write( "with each group including
\n" ); document.write( "5 peanuts, 2 hazelnuts, 2 cashews, and 1 pecan.\r
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