document.write( "Question 914378: A farmer uses 60metres of fencing to make three sides of a rectangular sheep pen, the fourth side being a wall. Find the length of the shorter sides of the pen if the area enclsed is 448 metre square
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Algebra.Com's Answer #555143 by josgarithmetic(39617)\"\" \"About 
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(\"shorter sides\", length to find, so these would not be along the wall).\r
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\n" ); document.write( "\n" ); document.write( "Dimensions x and y.
\n" ); document.write( "Fencing quantity is 60 meters, and area to enclose is 448 sq. m's.\r
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\n" ); document.write( "\n" ); document.write( "Assuming y is along the wall, and another length y is opposite the wall,
\n" ); document.write( "x would be one of the shorter sides.\r
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\n" ); document.write( "\n" ); document.write( "2x+y=60 to account for the length of fencing
\n" ); document.write( "and
\n" ); document.write( "xy=448 for the area.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28system%282x%2By=60%2Cxy=448%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute for y in the area equation:
\n" ); document.write( "\"x%2860-2x%29=448\"
\n" ); document.write( "simplify and solve first for x.
\n" ); document.write( "\"x%2830-x%29=224\"
\n" ); document.write( "\"-x%5E2%2B30x-224=0\"
\n" ); document.write( "\"highlight_green%28x%5E2-30x%2B224=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "Trying to factor that may be a chore, but the discriminant is \"30%5E2-4%2A224=4\", a perfect square.
\n" ); document.write( "\"x=%2830%2B-sqrt%284%29%29%2F2\"
\n" ); document.write( "\"x=%2832%2F2%29\" or \"x=28%2F2\"
\n" ); document.write( "\"x=16\" or \"x=14\"\r
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\n" ); document.write( "\n" ); document.write( "Earlier found y=60-2x.
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\n" ); document.write( "If x=16 then y=28.
\n" ); document.write( "If x=14 then y=32.
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