document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=914413>Question 914413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A greater number is seven less than three times the smaller number. If the sum of the two numbers is 13 find the number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555140 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s = the smaller number<BR>\n" );
document.write( "Let g = the greater number<BR>\n" );
document.write( "g = 3s - 7<BR>\n" );
document.write( "s + g = 13<BR>\n" );
document.write( "solve for g by adding -s to each side<BR>\n" );
document.write( "   g = 13 - s<BR>\n" );
document.write( "Substitute (13 - s) for g in g = 3s - 7<BR>\n" );
document.write( "(13 - s) = 3s - 7<BR>\n" );
document.write( "add s to each side<BR>\n" );
document.write( " 13 = 4s - 7<BR>\n" );
document.write( "add 7 to each side<BR>\n" );
document.write( " 20 = 4s<BR>\n" );
document.write( "divide each side by 4<BR>\n" );
document.write( " 5 = s<BR>\n" );
document.write( "Since g = 3s - 7, g = 3(5) - 7<BR>\n" );
document.write( "g = 15 - 7<BR>\n" );
document.write( "g = 8<BR>\n" );
document.write( "So the numbers are 5 and 8 .<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );