document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=914480>Question 914480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The numerator of a fraction is 7 less than the denominator. If 3 is added to the numerator and 9 is subtracted from the denominator the resulting fraction is equal to 3/2. Find the original fraction. \r<BR>\n" );
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document.write( "I tried the following, but am not finding the right answer:\r<BR>\n" );
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document.write( "\"Let x= denominator\"<BR>\n" );
document.write( "\"Let x-7= numerator\"\r<BR>\n" );
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document.write( "(X-9)+(x-7)+9=3/2<BR>\n" );
document.write( "2(x-9+x-7+9)= 3/2 (2/1)<BR>\n" );
document.write( "2x-18+2x-14+18=3<BR>\n" );
document.write( "4x-14=3<BR>\n" );
document.write( "4x=17<BR>\n" );
document.write( "X=17/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #555132 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=555132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-7/x<BR>\n" );
document.write( "(x-7+3)/(x-9)=3/2<BR>\n" );
document.write( "(x-4)/(x-9)=3/2<BR>\n" );
document.write( "2*(x-4)=3*(x-9)<BR>\n" );
document.write( "2x-8=3x-27<BR>\n" );
document.write( "x=19<BR>\n" );
document.write( "12/19 original fraction<BR>\n" );
document.write( "check<BR>\n" );
document.write( "12/19<BR>\n" );
document.write( "15/10=3/2<BR>\n" );
document.write( "ok </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );