document.write( "Question 914370: A man bicycle 52 miles in 5 hours, travelling at 8 m.p.h for x hours and at 12 m.p.h for y hours. Find x and y. \n" ); document.write( "
Algebra.Com's Answer #555120 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A man bicycle 52 miles in 5 hours, travelling at 8 m.p.h for x hours and at 12 m.p.h for y hours. \n" ); document.write( " Find x and y. \n" ); document.write( ": \n" ); document.write( "The time equation: \n" ); document.write( "x + y = 5 \n" ); document.write( "x = (5-y); we can use this form for substitution \n" ); document.write( ": \n" ); document.write( "The distance equation (dist = speed * time) \n" ); document.write( "8x + 12y = 52 \n" ); document.write( "replace x with (5-y) \n" ); document.write( "8(5-y) + 12y = 52 \n" ); document.write( "40 - 8y + 12y = 52 \n" ); document.write( "-8y + 12y = 52 - 40 \n" ); document.write( "4y = 12 \n" ); document.write( "y = 12/4 \n" ); document.write( "y = 3 hrs \n" ); document.write( "find x \n" ); document.write( "x + 3 = 5 \n" ); document.write( "x = 2 hrs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this in the distance equation \n" ); document.write( "8(2) + 12(3) = 52 \n" ); document.write( "16 + 36 = 52 \n" ); document.write( " \n" ); document.write( " |