document.write( "Question 914456: A jeweler has five rings, each weighing 16 grams, made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 80%.\r
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document.write( "(a) Construct a model that gives the fraction G(x) of the new alloy that is pure gold. (Let x represent the number of grams of silver added.) \n" );
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Algebra.Com's Answer #555117 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! 5 rings, 16 grams each ----> 5*16 = 80 grams total\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10% silver: 80*0.10 = 8 grams of pure silver \n" ); document.write( "90% gold: 80*0.90 = 72 grams of pure gold\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have 72 grams of pure gold out of 80 grams of alloy (silver + gold)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Currently, the fraction is 72/80. This leads to 9/10 = 90% gold\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now add x grams of pure silver. We do NOT add this to the 72 since that represents all gold. We add this to the 80 since that represents silver+gold.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have this fraction now: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the model is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We want the gold fraction to be equal to 80/100 (ie 80%), so \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to add 10 grams of pure silver to get an 80% gold alloy.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let me know if you need more help or if you need me to explain a step in more detail. \n" ); document.write( "Feel free to email me at jim_thompson5910@hotmail.com \n" ); document.write( "or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thanks,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |