document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=914188>Question 914188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 15. Three times one of the number is 11 less than 5 times the other. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554990 by </B><A HREF=/tutors/aboutme.mpl?userid=fave><B>fave(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fave><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fave><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let a and b represent the numbers<BR>\n" );
document.write( " a+b=15 from the first statement<BR>\n" );
document.write( " 3a=5b-11 from the second statement<BR>\n" );
document.write( "make b the subject of formular in the first equation<BR>\n" );
document.write( "  b=15-a<BR>\n" );
document.write( "substitute b into the second equation<BR>\n" );
document.write( "  3a=5(15-a)-11<BR>\n" );
document.write( "  3a=75-5a-11<BR>\n" );
document.write( "  3a=64-5a<BR>\n" );
document.write( "  3a+5a=64<BR>\n" );
document.write( "  a=8<BR>\n" );
document.write( "from the first equation,a+b=15,so b=15-8=7<BR>\n" );
document.write( "the numbers are 8 and 7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );