document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=914277>Question 914277</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a right triangle is 7 inches longer than the base and 14 inches longer than te height the perimeter of the triangle is 84 inches find its area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554982 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a right triangle is 7 inches longer than the base and 14 inches longer than te height the perimeter of the triangle is 84 inches find its area<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=length of hypotenuse<BR>\n" );
document.write( "base,b=x-7<BR>\n" );
document.write( "height=x-14<BR>\n" );
document.write( "x+x-7+x-14=84<BR>\n" );
document.write( "3x-21=84<BR>\n" );
document.write( "3x=105<BR>\n" );
document.write( "x=35<BR>\n" );
document.write( "area=1/2*base*height=1/2(x-7)(x-14)=1/2(28)(21)=294 sq inches </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );