document.write( "Question 914267: beth is 6 years older than pia , find their present age if the product of beth's age 5 years from now and pia's age 6 years ago is 53. \n" ); document.write( "
Algebra.Com's Answer #554972 by josgarithmetic(39617)\"\" \"About 
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b, beth now
\n" ); document.write( "p, pia now\r
\n" ); document.write( "\n" ); document.write( "b=p+6.\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%2B5%29%28p-6%29=53\" according to description.
\n" ); document.write( "\"%28p%2B6%2B5%29%28p-6%29=53\" when substitute for b.
\n" ); document.write( "\"%28p%2B11%29%28p-6%29=53\"
\n" ); document.write( "\"p%5E2%2B5p-66=53\"
\n" ); document.write( "\"p%5E2%2B5p-13=0\", not factorable.\r
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\n" ); document.write( "\n" ); document.write( "\"p=%28-5%2Bsqrt%2825%2B4%2A13%29%29%2F2\"
\n" ); document.write( "\"highlight%28p=%28sqrt%2877%29-5%29%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "and you can try to simplify for beth's age, \"highlight%28b=%28sqrt%2877%29-5%29%2F2%2B6%29\"\r
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\n" ); document.write( "\n" ); document.write( "---
\n" ); document.write( "\"sqrt%2877%29=8.775\" approx.
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