document.write( "Question 914256: The sum of eight consecutive odd numbers is 192.Find the last number of the sequence. \n" ); document.write( "
Algebra.Com's Answer #554956 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint:\r
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\n" ); document.write( "\n" ); document.write( "First Number: x
\n" ); document.write( "Second Number: x+2
\n" ); document.write( "Third Number: x+4
\n" ); document.write( "Fourth Number: x+6
\n" ); document.write( "Fifth Number: x+8
\n" ); document.write( "Sixth Number: x+10
\n" ); document.write( "Seventh Number: x+12
\n" ); document.write( "Eighth Number: x+14\r
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\n" ); document.write( "\n" ); document.write( "Add up all the numbers and then set that sum equal to 192\r
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\n" ); document.write( "\n" ); document.write( "x+(x+2)+(x+4)+(x+6)+(x+8)+(x+10)+(x+12)+(x+14) = 192\r
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\n" ); document.write( "\n" ); document.write( "Solve for x. I'll let you do this part. Once you have the value of x, use it to find the value of x+14.
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