document.write( "Question 914189: Evaluate the log expression: \r
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document.write( "So I know that log(base a)(b^r) = r log (base) b
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document.write( "But I get lost on how to continue to break it down further from that it wouldn't be log(base 8) (20^8)?\r
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document.write( "Please help me figure this out \n" );
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Algebra.Com's Answer #554922 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=8^(log(20)/log(8))\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=8^(log(2^2*5)/log(2^3))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=8^((2log(2)+log(5))/(3log(2))) ......plug in values\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=8^((2(0.30102)+(0.69897))/(3(0.30102)))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=8^((0.60204+0.69897)/0.90306))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=8^(1.30101/0.90306)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |