document.write( "Question 914189: Evaluate the log expression: \"8%5E%28%28log%28%28base8%29%2920%29%29\"\r
\n" ); document.write( "\n" ); document.write( "So I know that log(base a)(b^r) = r log (base) b
\n" ); document.write( "But I get lost on how to continue to break it down further from that it wouldn't be log(base 8) (20^8)?\r
\n" ); document.write( "\n" ); document.write( "Please help me figure this out
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Algebra.Com's Answer #554922 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"8%5E%28%28log%288%2C20%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "=8^(log(20)/log(8))\r
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\n" ); document.write( "\n" ); document.write( "=8^(log(2^2*5)/log(2^3))\r
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\n" ); document.write( "\n" ); document.write( "=8^((2log(2)+log(5))/(3log(2))) ......plug in values\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%29=0.30102\"\r
\n" ); document.write( "\n" ); document.write( "\"log%285%29=0.69897\"\r
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\n" ); document.write( "\n" ); document.write( "=8^((2(0.30102)+(0.69897))/(3(0.30102)))\r
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\n" ); document.write( "\n" ); document.write( "=8^((0.60204+0.69897)/0.90306))\r
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\n" ); document.write( "\n" ); document.write( "=8^(1.30101/0.90306)\r
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\n" ); document.write( "\n" ); document.write( "=\"8%5E1.44066\"\r
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\n" ); document.write( "\n" ); document.write( "=\"20.0007\" round\r
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\n" ); document.write( "\n" ); document.write( "=\"20\"\r
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